Accept 3-digit number and Reverse it

#include<iostream.h>
#include<conio.h>

void main()
{
    int r = 0, no, s = 0, k;
    clrscr();

    cout<<:Enter a number :";
    cin>>no;

    k = no;

    while(no != 10)
    {
        r = no % 10;
        no = no / 10;
        s = s * 10 + r;
    }

    cout<<"Reverse is :"<<s;

    if(k == s)
        cout<<"Original number and Reversed number are same";
    else
        cout<<"Original number and Reversed number are not same";
}